Method sumDigits takes a non-negative integer and returns the sum of its base-10 digits. For example, sumDigits (1234) returns $1 + 2 + 3 + 4 = 10$. Note that it is easy to split an integer into two smaller pieces by dividing by 10 (e.g., 1234/10 = 123, and 1234 % 10 = 4).
#include<iostream>
using namespace std;
int sum_of_digit(int num)
{
if (num == 0)
{
return 0;
}
return (num % 10 + sum_of_digit(num / 10));
}
int main()
{
int num;
int result;
cout<<"Enter Number = ";
cin>>num;
result = sum_of_digit(num);
cout << "Sum of digits 1 + 2 + 3 + ... + "<< num <<" is "<<" = "<<result << endl;
return 0;
}
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